Description
Returns a 3D vector containing the position, tangent in U
direction, normal and bi-normal at a given U value.
C# Syntax
Object NurbsCurve.EvaluatePosition( Double in_dUValue );
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Scripting Syntax
oArray = NurbsCurve.EvaluatePosition( UValue );
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Return Value
A 1-dimensional Array
containing the position, tangent, normal and bi-normal.
Parameters
| Parameter |
Type |
Description |
| UValue |
Double |
The U Value at which we want to evaluate the curve. |
Examples
1. VBScript Example
set oRoot = Application.ActiveProject.ActiveScene.Root
set oArc = oRoot.AddGeometry( "Arc", "NurbsCurve" )
aValues = oArc.ActivePrimitive.Geometry.Curves(0).EvaluatePosition( 3.0 )
set oPosition = aValues(0)
logmessage "The position at 3.0 is x :" & oPosition.x & " y: " _
& oPosition.y & " z: " & oPosition.z
set oUTangent = aValues(1)
logmessage "The tangent in U at 3.0 is x :" & oUTangent.x & " y: " _
& oUTangent.y & " z: " & oUTangent.z
set oNormal = aValues(2)
logmessage "The normal at 3.0 is x :" & oNormal.x & " y: " & oNormal.y _
& " z: " & oNormal.z
set oBiNormal = aValues(3)
logmessage "The bi-normal at 3.0 is x :" & oBiNormal.x & " y: " _
& oBiNormal.y & " z: " & oBiNormal.z
' Expected result:
'INFO : The position at 3.0 is x :1.16113870901785 y: 3.82776134292884 z: 0
'INFO : The tangent in U at 3.0 is x :0.956940009306386 y: -0.290285753334009 z: 0
'INFO : The normal at 3.0 is x :-0.290285753334009 y: -0.956940009306387 z: 0
'INFO : The bi-normal at 3.0 is x :0 y: 0 z: -1
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2. JScript Example
/*
See also the JScript example for NurbsCurveList.GetClosestCurvePosition2 which demonstrates
how to use NurbsCurveList.GetClosestCurvePosition2 and NurbsCurve.EvaluatePosition as an
(object model) alternative to the EvaluateCurveAt command.
*/
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See Also
