Object Model: NurbsCurve.EvaluateNormalizedPosition

NurbsCurve.EvaluateNormalizedPosition

Description

Returns a 3D vector containing the position, tangent vector in U direction, normal and bi-normal at a given normalized U value.

C# Syntax

Object NurbsCurve.EvaluateNormalizedPosition( Double in_dUValueNormalized );

Scripting Syntax

oArray = NurbsCurve.EvaluateNormalizedPosition( UValueNormalized );

Return Value

A 1-dimensional Array containing the position, tangent vector, normal and bi-normal.

Parameters

Parameter	Type	Description
UValueNormalized	Double	The normalized UValue(0.0 to 1.0) at which we want to evaluate the curve.

Examples

VBScript Example

set oRoot = Application.ActiveProject.ActiveScene.Root
set oArc = oRoot.AddGeometry( "Arc", "NurbsCurve" )
aValues = oArc.ActivePrimitive.Geometry.Curves(0).EvaluateNormalizedPosition( 0.5 )
set oPosition = aValues(0)
logmessage "The position at 0.5 is x :" &  oPosition.x      & " y: " & oPosition.y & " z: " & oPosition.z
set oUTangent = aValues(1)
logmessage "The tangent in U at 0.5 is x :" & oUTangent.x & " y: " & oUTangent.y & " z: " & oUTangent.z
set oNormal = aValues(2)
logmessage "The normal at 0.5 is x :" & oNormal.x & " y: " & oNormal.y & " z: " & oNormal.z
set oBiNormal = aValues(3)
logmessage "The bi-normal at 0.5 is x :" & oBiNormal.x & " y: " & oBiNormal.y & " z: " & oBiNormal.z