Creates a curve of the specified degree.
Note: This command uses output arguments. C# and some
scripting languages (such as JScript, PerlScript and Python) don't support arguments passed by reference so you
need to use the best workaround for your situation:
For scripting languages this command returns an ISIVTCollection
which you can use to get the output arguments.
For C# you can use the XSIApplication.ExecuteCommand method to call this command. ExecuteCommand
packs the output arguments into a C# System.Object containing an Array of the output arguments (see
Calling Commands from C#).
CreateCurve( [Degree], CurveType, [Points], [Local], [Value] ); |
Parameter | Type | Description | ||||||
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Degree | Integer |
Degree of curve Default Value: 3
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CurveType | Integer |
Specifies whether the curve is interpolated Default Value: 1
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Points | String | Comma-separated list of points. At least one point is necessary. For example, "(0,1,0),(0,2,0),(3,3,0)". | ||||||
Local | Boolean |
True if points are in local coordinates, False if they are in global coordinates. Default Value: False |
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Value | X3DObject | Returns the curve |
' This example creates curves: ' 1) Cubic non-interpolated curve ' 2) Cubic interpolated curve ' 3) Linear non-interpolated curve ' NOTE: That a linear interpolated curve will give the same trace as linear non-interpolated curve. ' NOTE: Put no spaces in point list. newscene Dim CubicInterpolated, CubicNonInterpolated, LinearNonInterpolated 'Create curves. Points are in global coordinates. CreateCurve 3, 0, "(-2,0,0),(-2,0,-2),(2,0,-2),(2,0,0)", FALSE, CubicNonInterpolated CreateCurve 3, 1, "(-2,0,0),(-2,0,-2),(2,0,-2),(2,0,0)", FALSE, CubicInterpolated CreateCurve 1, 0, "(-2,0,0),(-2,0,-2),(2,0,-2),(2,0,0)", FALSE, LinearNonInterpolated 'Name the curves. SetValue CubicNonInterpolated & ".Name", "CubicNonInterpolated" SetValue CubicInterpolated & ".Name", "CubicInterpolated" SetValue LinearNonInterpolated & ".Name", "LinearNonInterpolated" |