Object Model: XSIUtils.IsLinuxOS

XSIUtils.IsLinuxOS

XSIUtils.IsLinuxOS

Introduced

v5.0

Description

Returns true if Softimage is running on a Linux Operating System. This method is useful when writing cross-platform scripts.

C# Syntax

Boolean XSIUtils.IsLinuxOS();

Scripting Syntax

oReturn = XSIUtils.IsLinuxOS();

Return Value

Returns true if Softimage is running on a Linux-based operating system

See Also

XSIUtils.IsWindowsOS XSIUtils.IsFileSystemCaseSensitive XSIUtils.Is64BitOS XSIApplication.Platform